(4)/(3x^2-5x^4)^4

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Solution for (4)/(3x^2-5x^4)^4 equation:


D( x )

(3*x^2-(5*x^4))^4 = 0

(3*x^2-(5*x^4))^4 = 0

(3*x^2-(5*x^4))^4 = 0

(3*x^2-5*x^4)^4 = 0

3*x^2-5*x^4 = 0

x^2*(3-5*x^2) = 0

-5*x^2 = -3 // : -5

x^2 = 3/5

x^2 = 3/5 // ^ 1/2

abs(x) = (3/5)^(1/2)

x = (3/5)^(1/2) or x = -(3/5)^(1/2)

x^2*(x-(3/5)^(1/2))*(x+(3/5)^(1/2)) = 0

(x^2)^4*(x-(3/5)^(1/2))^4*(x+(3/5)^(1/2))^4 = 0

( x+(3/5)^(1/2) )

x+(3/5)^(1/2) = 0 // - (3/5)^(1/2)

x = -(3/5)^(1/2)

( x-(3/5)^(1/2) )

x-(3/5)^(1/2) = 0 // + (3/5)^(1/2)

x = (3/5)^(1/2)

( x^2 )

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:-(3/5)^(1/2)) U (-(3/5)^(1/2):0) U (0:(3/5)^(1/2)) U ((3/5)^(1/2):+oo)

4/((3*x^2-(5*x^4))^4) = 0

4/((3*x^2-5*x^4)^4) = 0

3*x^2-5*x^4 = 0

x^2*(3-5*x^2) = 0

-5*x^2 = -3 // : -5

x^2 = 3/5

x^2 = 3/5 // ^ 1/2

abs(x) = (3/5)^(1/2)

x = (3/5)^(1/2) or x = -(3/5)^(1/2)

x^2*(x-(3/5)^(1/2))*(x+(3/5)^(1/2)) = 0

4/((x^2)^4*(x-(3/5)^(1/2))^4*(x+(3/5)^(1/2))^4) = 0

4 = 0

x belongs to the empty set

x belongs to the empty set

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